UNDERSTAND IT. WORK IT OUT.

Learn: Circle second moment of area

This geometric property describes how area is spread away from an axis for bending about a centroidal diameter. It is not the area of the circle and it is not a mass moment of inertia.

Beginner-friendlyFree · No accountTwo worked examples + separate practice
01

What the formula is saying

The diameter is raised to the fourth power, making section size very influential. For this axis, integration over the solid circle gives the multiplier π/64.

I = π D⁴ / 64

Read the symbols in plain language

D
Diameter

Diameter. Area farther from the axis contributes strongly, producing a fourth-power size dependence.

m

Metres measure length; 1 m = 1000 mm.

I
Result to find

Circle second moment of area. Multiply by π and divide by 64 for the specified axis of the solid circle.

m⁴

Sort out the units first

Use a diameter in metres to obtain m⁴. Converting a length unit requires the fourth power: 1 m⁴ = 10¹² mm⁴. The calculator converts the diameter before applying the power.

Assumptions before calculating

The cross-section is a complete solid circle with uniform geometry. The specified axis passes through its centre; the diameter is strictly positive.

02

Let’s solve one together

Read the given values, follow each operation, then check what the result means.

Read the supplied values as one complete study case. Find I and explain the result in the stated output unit.

D · Diameter
0.3 m
  1. Raise the diameter to the fourth power

    Area farther from the axis contributes strongly, producing a fourth-power size dependence.

    (0.3)^4 = 0.0081 m⁴
  2. Apply the circular-section factor

    Multiply by π and divide by 64 for the specified axis of the solid circle.

    π × (0.0081) ÷ 64 ≈ 0.0003976078202 m⁴
Answer0.0003976078202 m⁴

Does this worked answer make sense?

Doubling the diameter multiplies the result by 16. For the same solid circle, the polar value is twice the value about one centroidal diameter.

A second worked example — different values

A second case uses different data. Predict which way the answer will change, then calculate it without reusing the first answer.

D · Diameter
0.2 m
  1. Raise the diameter to the fourth power

    Area farther from the axis contributes strongly, producing a fourth-power size dependence.

    (0.2)^4 = 0.0016 m⁴
  2. Apply the circular-section factor

    Multiply by π and divide by 64 for the specified axis of the solid circle.

    π × (0.0016) ÷ 64 ≈ 0.00007853981634 m⁴
Answer0.00007853981634 m⁴
03

Now try your own values

Change a value or its unit. The same method will show your calculation, step by step.

Diameter. Area farther from the axis contributes strongly, producing a fourth-power size dependence.

English, Arabic and Persian digits are supported. The steps convert inputs to the formula’s base units.

Results update only when you calculate. The lesson example above stays unchanged.

04

Your turn — check your understanding

Solve this separate case yourself. Use only the values below; the two worked examples use different data. Give the requested result in the selected unit.

D · Diameter
0.15 m

Find: Learn: Circle second moment of area

For repeating decimals, use at least four significant figures. Accepted rounding tolerance: 0.05% of the expected value; zero uses an absolute tolerance of 10⁻¹².

A hint, not the answer

The diameter is raised to the fourth power, making section size very influential. For this axis, integration over the solid circle gives the multiplier π/64.

Use a diameter in metres to obtain m⁴. Converting a length unit requires the fourth power: 1 m⁴ = 10¹² mm⁴. The calculator converts the diameter before applying the power.

Show the full practice solution

Compare the steps with your work; revealing a solution does not mark the lesson complete.

  1. Raise the diameter to the fourth power

    Area farther from the axis contributes strongly, producing a fourth-power size dependence.

    (0.15)^4 = 0.00050625 m⁴
  2. Apply the circular-section factor

    Multiply by π and divide by 64 for the specified axis of the solid circle.

    π × (0.00050625) ÷ 64 ≈ 0.00002485048876 m⁴
Answer0.00002485048876 m⁴

Avoid the common trap

Use the diameter, not the radius. Do not confuse I = πD⁴/64 with J = πD⁴/32. A unit written m⁴ must not be reported as m².

When this method applies — and when it does not

For a hollow circle, subtract the inner-circle property from the outer-circle property. Do not use the solid-circle expression for a tube, or use a polar area moment as the torsion constant of a noncircular section.

For study and understanding, not approval of a real structure, site operation or design. Apply the correct standard, National Annex and professional review to actual engineering work.

One idea understood. Keep going.

This optional checkmark is saved only in this browser. It is your own progress note, not a certificate.

Sources & further reading

References open in a new tab and explain the underlying principles. The teaching text and examples here are SimpleFlick’s own; the source organisations have not endorsed this calculator.

Reading focus: Circle second moment of area. Use the relevant elastic-response, equilibrium, constitutive-relations or shear-and-torsion module; the lesson states its particular sign convention.

Lesson updated: · Both examples and the separate practice case are checked against an independent high-precision numerical implementation. This verifies arithmetic for the stated model, not engineering certification.

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