UNDERSTAND IT. WORK IT OUT.

Learn: Darcy–Weisbach friction loss

Flow along a pipe loses mechanical energy through wall friction. The Darcy–Weisbach relationship converts pipe length, diameter, speed and a supplied friction factor into an equivalent lost head.

Beginner-friendlyFree · No accountTwo worked examples + separate practice
01

What the formula is saying

First form L/D, the number of pipe diameters along the length. Multiply by the Darcy friction factor and the velocity head v²/(2g). A long narrow pipe produces more loss at the same velocity and friction factor.

hf = f (L/D) v²/(2g)

Read the symbols in plain language

f
Darcy friction factor

Dimensionless Darcy–Weisbach pipe-loss factor. It is four times the Fanning factor for the same flow.

ratio / no unit

A dimensionless ratio has no physical unit; 0.01 as a ratio is 1% when the percent option is selected.

L
Pipe length

Pipe length. Dividing two lengths gives the dimensionless length-to-diameter ratio.

m

Metres measure length; 1 m = 1000 mm.

D
Diameter

Diameter. Dividing two lengths gives the dimensionless length-to-diameter ratio.

m

Metres measure length; 1 m = 1000 mm.

v
Velocity

Velocity. Friction loss scales with squared speed rather than speed alone.

m/s

Use m/s as the base unit shown here. L and internal diameter D must use the same length unit, here m. f is the Darcy factor, dimensionless; velocity is m/s and g is m/s². The result is m of liquid head, not pressure in Pa.

g
Gravity

Gravity. Friction loss scales with squared speed rather than speed alone.

m/s²

Use m/s² as the base unit shown here. L and internal diameter D must use the same length unit, here m. f is the Darcy factor, dimensionless; velocity is m/s and g is m/s². The result is m of liquid head, not pressure in Pa.

hf
Result to find

Darcy–Weisbach friction loss. Multiplying the dimensionless factors by velocity head yields head loss.

m

Sort out the units first

L and internal diameter D must use the same length unit, here m. f is the Darcy factor, dimensionless; velocity is m/s and g is m/s². The result is m of liquid head, not pressure in Pa.

Assumptions before calculating

Assume steady incompressible flow through a constant-diameter full pipe, with a Darcy factor appropriate to Reynolds number and relative roughness. Use an average velocity for that pipe reach.

02

Let’s solve one together

Read the given values, follow each operation, then check what the result means.

Read the supplied values as one complete study case. Find hf and explain the result in the stated output unit.

f · Darcy friction factor
0.02
L · Pipe length
100 m
D · Diameter
0.2 m
v · Velocity
2 m/s
g · Gravity
9.81 m/s²
  1. Count pipe diameters along the reach

    Dividing two lengths gives the dimensionless length-to-diameter ratio.

    (100) ÷ (0.2) = 500
  2. Find the velocity-head scale

    Friction loss scales with squared speed rather than speed alone.

    (2)^2 ÷ (2 × (9.81)) ≈ 0.2038735984 m
  3. Apply the Darcy friction factor

    Multiplying the dimensionless factors by velocity head yields head loss.

    (0.02) × (500) × (0.2038735984) ≈ 2.038735984 m
Answer2.038735984 m

Does this worked answer make sense?

At fixed f, L and D, doubling speed multiplies loss by four. Zero length or zero speed gives zero friction loss within this model.

A second worked example — different values

A second case uses different data. Predict which way the answer will change, then calculate it without reusing the first answer.

f · Darcy friction factor
0.025
L · Pipe length
80 m
D · Diameter
0.15 m
v · Velocity
1.8 m/s
g · Gravity
9.81 m/s²
  1. Count pipe diameters along the reach

    Dividing two lengths gives the dimensionless length-to-diameter ratio.

    (80) ÷ (0.15) ≈ 533.3333333
  2. Find the velocity-head scale

    Friction loss scales with squared speed rather than speed alone.

    (1.8)^2 ÷ (2 × (9.81)) ≈ 0.1651376147 m
  3. Apply the Darcy friction factor

    Multiplying the dimensionless factors by velocity head yields head loss.

    (0.025) × (533.3333333) × (0.1651376147) ≈ 2.201834862 m
Answer2.201834862 m
03

Now try your own values

Change a value or its unit. The same method will show your calculation, step by step.

Dimensionless Darcy–Weisbach pipe-loss factor. It is four times the Fanning factor for the same flow.

Pipe length. Dividing two lengths gives the dimensionless length-to-diameter ratio.

Diameter. Dividing two lengths gives the dimensionless length-to-diameter ratio.

Velocity. Friction loss scales with squared speed rather than speed alone.

Gravity. Friction loss scales with squared speed rather than speed alone.

English, Arabic and Persian digits are supported. The steps convert inputs to the formula’s base units.

Results update only when you calculate. The lesson example above stays unchanged.

04

Your turn — check your understanding

Solve this separate case yourself. Use only the values below; the two worked examples use different data. Give the requested result in the selected unit.

f · Darcy friction factor
0.018
L · Pipe length
120 m
D · Diameter
0.25 m
v · Velocity
2.5 m/s
g · Gravity
9.81 m/s²

Find: Learn: Darcy–Weisbach friction loss

For repeating decimals, use at least four significant figures. Accepted rounding tolerance: 0.05% of the expected value; zero uses an absolute tolerance of 10⁻¹².

A hint, not the answer

First form L/D, the number of pipe diameters along the length. Multiply by the Darcy friction factor and the velocity head v²/(2g). A long narrow pipe produces more loss at the same velocity and friction factor.

L and internal diameter D must use the same length unit, here m. f is the Darcy factor, dimensionless; velocity is m/s and g is m/s². The result is m of liquid head, not pressure in Pa.

Show the full practice solution

Compare the steps with your work; revealing a solution does not mark the lesson complete.

  1. Count pipe diameters along the reach

    Dividing two lengths gives the dimensionless length-to-diameter ratio.

    (120) ÷ (0.25) = 480
  2. Find the velocity-head scale

    Friction loss scales with squared speed rather than speed alone.

    (2.5)^2 ÷ (2 × (9.81)) ≈ 0.3185524975 m
  3. Apply the Darcy friction factor

    Multiplying the dimensionless factors by velocity head yields head loss.

    (0.018) × (480) × (0.3185524975) ≈ 2.752293578 m
Answer2.752293578 m

Avoid the common trap

Do not substitute a Fanning factor directly: the Darcy factor is four times the Fanning factor. Do not use pipe radius for D or add this head loss to a pressure without conversion.

When this method applies — and when it does not

The factor is supplied here; it must come from a suitable laminar or turbulent relation. Fittings and entrances create additional losses. Changing diameter at fixed discharge also changes velocity, so the fixed-velocity comparison is not a complete resizing study.

For study and understanding, not approval of a real structure, site operation or design. Apply the correct standard, National Annex and professional review to actual engineering work.

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Sources & further reading

References open in a new tab and explain the underlying principles. The teaching text and examples here are SimpleFlick’s own; the source organisations have not endorsed this calculator.

Reading focus: Darcy–Weisbach friction loss. Water-measurement principles; for discharge devices, read the orifice/weir chapters and the installation and head-measurement conditions, not only the coefficient formula.

Lesson updated: · Both examples and the separate practice case are checked against an independent high-precision numerical implementation. This verifies arithmetic for the stated model, not engineering certification.

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