UNDERSTAND IT. WORK IT OUT.

Learn: Footing load eccentricity

A vertical force and a moment can be represented by an equivalent force acting away from the footing centre. Eccentricity is the signed distance needed for that force to reproduce the supplied moment.

Beginner-friendlyFree · No accountTwo worked examples + separate practice
01

What the formula is saying

A moment equals force times perpendicular distance, M = N e. Rearranging gives e = M/N; the sign indicates which side of the reference the resultant acts on.

e = M / N

Read the symbols in plain language

M
Moment

Moment. Use the moment and compressive resultant from the same transferred load system.

kN·m

Use kN·m as the base unit shown here. Use M in kN·m and compressive N in kN, giving e in m. The force and moment must be taken at the same footing reference level.

N
Vertical load

Vertical load. Divide the signed moment by positive compressive force to recover a signed distance.

kN

Kilonewtons measure force; 1 kN = 1000 N.

e
Result to find

Footing load eccentricity. Divide the signed moment by positive compressive force to recover a signed distance.

m

Sort out the units first

Use M in kN·m and compressive N in kN, giving e in m. The force and moment must be taken at the same footing reference level.

Assumptions before calculating

A positive compressive vertical resultant exists and the moment is about the relevant footing centroidal axis. The lesson uses signed M and N > 0.

02

Let’s solve one together

Read the given values, follow each operation, then check what the result means.

Read the supplied values as one complete study case. Find e and explain the result in the stated output unit.

M · Moment
100 kN·m
N · Vertical load
1000 kN
  1. Identify the moment at the footing reference

    Use the moment and compressive resultant from the same transferred load system.

    (100) = 100 kN·m
  2. Find the equivalent force offset

    Divide the signed moment by positive compressive force to recover a signed distance.

    (100) ÷ (1000) = 0.1 m
Answer0.1 m

Does this worked answer make sense?

Zero moment gives zero eccentricity. Doubling N with M fixed halves e; doubling M doubles it.

A second worked example — different values

A second case uses different data. Predict which way the answer will change, then calculate it without reusing the first answer.

M · Moment
-120 kN·m
N · Vertical load
800 kN
  1. Identify the moment at the footing reference

    Use the moment and compressive resultant from the same transferred load system.

    (-120) = -120 kN·m
  2. Find the equivalent force offset

    Divide the signed moment by positive compressive force to recover a signed distance.

    (-120) ÷ (800) = -0.15 m
Answer-0.15 m
03

Now try your own values

Change a value or its unit. The same method will show your calculation, step by step.

Moment. Use the moment and compressive resultant from the same transferred load system.

Vertical load. Divide the signed moment by positive compressive force to recover a signed distance.

English, Arabic and Persian digits are supported. The steps convert inputs to the formula’s base units.

Results update only when you calculate. The lesson example above stays unchanged.

04

Your turn — check your understanding

Solve this separate case yourself. Use only the values below; the two worked examples use different data. Give the requested result in the selected unit.

M · Moment
150 kN·m
N · Vertical load
1200 kN

Find: Learn: Footing load eccentricity

For repeating decimals, use at least four significant figures. Accepted rounding tolerance: 0.05% of the expected value; zero uses an absolute tolerance of 10⁻¹².

A hint, not the answer

A moment equals force times perpendicular distance, M = N e. Rearranging gives e = M/N; the sign indicates which side of the reference the resultant acts on.

Use M in kN·m and compressive N in kN, giving e in m. The force and moment must be taken at the same footing reference level.

Show the full practice solution

Compare the steps with your work; revealing a solution does not mark the lesson complete.

  1. Identify the moment at the footing reference

    Use the moment and compressive resultant from the same transferred load system.

    (150) = 150 kN·m
  2. Find the equivalent force offset

    Divide the signed moment by positive compressive force to recover a signed distance.

    (150) ÷ (1200) = 0.125 m
Answer0.125 m

Avoid the common trap

Do not divide force by moment. Do not mix moments from one level with forces from another without transfer, or remove the moment sign before understanding the resultant location.

When this method applies — and when it does not

Eccentricity alone does not determine the contact area or bearing pressure. Full contact, uplift, effective-width design, biaxial moments, settlement and stability need further checks. Near-zero N makes this representation highly sensitive.

For study and understanding, not approval of a real structure, site operation or design. Apply the correct standard, National Annex and professional review to actual engineering work.

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Sources & further reading

References open in a new tab and explain the underlying principles. The teaching text and examples here are SimpleFlick’s own; the source organisations have not endorsed this calculator.

Reading focus: Footing load eccentricity. Read the relevant soil phase, seepage, earth-pressure, settlement or foundation topic. Effective stress, drainage and idealized geometry determine whether the relationship applies.

Lesson updated: · Both examples and the separate practice case are checked against an independent high-precision numerical implementation. This verifies arithmetic for the stated model, not engineering certification.

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