UNDERSTAND IT. WORK IT OUT.

How to calculate gravitational potential energy

Lifting an object raises its gravitational potential energy relative to a reference height. The height reference must be stated because a height is never meaningful by itself.

Beginner-friendlyFree · No accountOne worked example + one practice problem
01

What the formula is saying

Near Earth’s surface with constant g, weight is mg. Multiplying by height h gives PE = mgh. For an energy change, use the height change instead.

PE = m g h

Read the symbols in plain language

m
Masskg
g
Gravitym/s²
h
Heightm

Sort out the units first

Use kg, m/s² and vertical metres to obtain joules. The example uses 2 m above the chosen zero level.

02

Let’s solve one together

Read the given values, follow each operation, then check what the result means.

m · Mass
50 kg
g · Gravity
9.81 m/s²
h · Height
2 m
  1. Find the weight

    Mass times g gives the downward gravitational force magnitude.

    (50) × (9.81) = 490.5 N
  2. Multiply by vertical height

    Use vertical rise, not distance travelled along a ramp.

    (490.5) × (2) = 981 J
Answer981 J

Does this worked answer make sense?

Doubling mass or height doubles the energy relative to the same reference. The worked result is 981 J.

03

Now try your own values

Change a value or its unit. The same method will show your calculation, step by step.

English, Arabic and Persian digits are supported. The steps convert inputs to the formula’s base units.

Results update only when you calculate. The lesson example above stays unchanged.

04

Your turn — check your understanding

Use these new values. Work it out first, then check your answer.

m · Mass
20 kg
g · Gravity
9.81 m/s²
h · Height
3 m

Find: gravitational potential energy

For repeating decimals, use at least four significant figures. Accepted rounding tolerance: 0.05% of the expected value; zero uses an absolute tolerance of 10⁻¹².

A hint, not the answer

Near Earth’s surface with constant g, weight is mg. Multiplying by height h gives PE = mgh. For an energy change, use the height change instead.

Use kg, m/s² and vertical metres to obtain joules. The example uses 2 m above the chosen zero level.

Show the full practice solution

Compare the steps with your work; revealing a solution does not mark the lesson complete.

  1. Find the weight

    Mass times g gives the downward gravitational force magnitude.

    (20) × (9.81) = 196.2 N
  2. Multiply by vertical height

    Use vertical rise, not distance travelled along a ramp.

    (196.2) × (3) = 588.6 J
Answer588.6 J

Avoid the common trap

Ramp length is not h. A negative potential energy can simply mean the point is below the chosen zero, not that the calculation is broken.

When this method applies — and when it does not

Uniform gravitational field approximation. This is not the general gravitational potential formula for large changes in distance from Earth.

For study and understanding, not approval of a real structure, site operation or design. Apply the correct standard, National Annex and professional review to actual engineering work.

One idea understood. Keep going.

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Sources & further reading

References open in a new tab and explain the underlying principles. The teaching text and examples here are SimpleFlick’s own; the source organisations have not endorsed this calculator.

Lesson updated: · Worked examples checked against the implemented formula; not an independent engineering certification.

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