UNDERSTAND IT. WORK IT OUT.

Learn: Horizontal-curve radius

A vehicle following a horizontal curve needs inward acceleration. Superelevation and available side friction contribute to that demand in a simplified road-curve balance.

Beginner-friendlyFree · No accountTwo worked examples + separate practice
01

What the formula is saying

Square speed v and divide by g(e + f). The denominator combines the supplied superelevation and side-friction contributions; their sum must be positive.

R = v²/[g(e+f)]

Read the symbols in plain language

v
Design speed

Design speed. Rearranging v squared over radius gives the radius for the stated speed and acceleration.

m/s

Use m/s as the base unit shown here. Use speed in m/s, not km/h; divide km/h by 3.6. e and f are decimal ratios, so 6% superelevation is 0.06. g is m/s² and radius R is m.

g
Gravity

Gravity. Gravity converts the dimensionless combined ratio into acceleration.

m/s²

Use m/s² as the base unit shown here. Use speed in m/s, not km/h; divide km/h by 3.6. e and f are decimal ratios, so 6% superelevation is 0.06. g is m/s² and radius R is m.

e
Superelevation as decimal

Superelevation as decimal. Use consistent decimal ratios and retain the sign of any adverse superelevation.

ratio / no unit

A dimensionless ratio has no physical unit; 0.01 as a ratio is 1% when the percent option is selected.

f
Side-friction factor

Side-friction factor. Use consistent decimal ratios and retain the sign of any adverse superelevation.

ratio / no unit

A dimensionless ratio has no physical unit; 0.01 as a ratio is 1% when the percent option is selected.

R
Result to find

Horizontal-curve radius. Rearranging v squared over radius gives the radius for the stated speed and acceleration.

m

Sort out the units first

Use speed in m/s, not km/h; divide km/h by 3.6. e and f are decimal ratios, so 6% superelevation is 0.06. g is m/s² and radius R is m.

Assumptions before calculating

Assume a steady-speed vehicle, a circular horizontal path and the usual small-angle road-banking approximation. Use a side-friction value and signed superelevation that are appropriate to the stated study conditions.

02

Let’s solve one together

Read the given values, follow each operation, then check what the result means.

Read the supplied values as one complete study case. Find R and explain the result in the stated output unit.

v · Design speed
22.22 m/s
g · Gravity
9.81 m/s²
e · Superelevation as decimal
0.06
f · Side-friction factor
0.15
  1. Combine the stated lateral contributions

    Use consistent decimal ratios and retain the sign of any adverse superelevation.

    (0.06) + (0.15) = 0.21
  2. Form the available lateral-acceleration scale

    Gravity converts the dimensionless combined ratio into acceleration.

    (9.81) × (0.21) = 2.0601 m/s²
  3. Solve the circular-path acceleration relation

    Rearranging v squared over radius gives the radius for the stated speed and acceleration.

    (22.22)^2 ÷ (2.0601) ≈ 239.6623465 m
Answer239.6623465 m

Does this worked answer make sense?

At fixed e and f, twice the speed requires four times the radius in this model. A larger positive combined lateral contribution reduces the calculated radius, but its permitted value cannot be chosen merely to obtain a smaller answer.

A second worked example — different values

A second case uses different data. Predict which way the answer will change, then calculate it without reusing the first answer.

v · Design speed
20 m/s
g · Gravity
9.81 m/s²
e · Superelevation as decimal
0.04
f · Side-friction factor
0.12
  1. Combine the stated lateral contributions

    Use consistent decimal ratios and retain the sign of any adverse superelevation.

    (0.04) + (0.12) = 0.16
  2. Form the available lateral-acceleration scale

    Gravity converts the dimensionless combined ratio into acceleration.

    (9.81) × (0.16) = 1.5696 m/s²
  3. Solve the circular-path acceleration relation

    Rearranging v squared over radius gives the radius for the stated speed and acceleration.

    (20)^2 ÷ (1.5696) ≈ 254.841998 m
Answer254.841998 m
03

Now try your own values

Change a value or its unit. The same method will show your calculation, step by step.

Design speed. Rearranging v squared over radius gives the radius for the stated speed and acceleration.

Gravity. Gravity converts the dimensionless combined ratio into acceleration.

Superelevation as decimal. Use consistent decimal ratios and retain the sign of any adverse superelevation.

Side-friction factor. Use consistent decimal ratios and retain the sign of any adverse superelevation.

English, Arabic and Persian digits are supported. The steps convert inputs to the formula’s base units.

Results update only when you calculate. The lesson example above stays unchanged.

04

Your turn — check your understanding

Solve this separate case yourself. Use only the values below; the two worked examples use different data. Give the requested result in the selected unit.

v · Design speed
25 m/s
g · Gravity
9.81 m/s²
e · Superelevation as decimal
0.05
f · Side-friction factor
0.15

Find: Learn: Horizontal-curve radius

For repeating decimals, use at least four significant figures. Accepted rounding tolerance: 0.05% of the expected value; zero uses an absolute tolerance of 10⁻¹².

A hint, not the answer

Square speed v and divide by g(e + f). The denominator combines the supplied superelevation and side-friction contributions; their sum must be positive.

Use speed in m/s, not km/h; divide km/h by 3.6. e and f are decimal ratios, so 6% superelevation is 0.06. g is m/s² and radius R is m.

Show the full practice solution

Compare the steps with your work; revealing a solution does not mark the lesson complete.

  1. Combine the stated lateral contributions

    Use consistent decimal ratios and retain the sign of any adverse superelevation.

    (0.05) + (0.15) = 0.2
  2. Form the available lateral-acceleration scale

    Gravity converts the dimensionless combined ratio into acceleration.

    (9.81) × (0.2) = 1.962 m/s²
  3. Solve the circular-path acceleration relation

    Rearranging v squared over radius gives the radius for the stated speed and acceleration.

    (25)^2 ÷ (1.962) ≈ 318.5524975 m
Answer318.5524975 m

Avoid the common trap

Do not insert 80 km/h as 80 m/s or use 6 instead of 0.06 for a 6% bank. Do not allow e + f to be zero or negative and then accept the resulting algebraic radius.

When this method applies — and when it does not

The output is a model radius for the supplied values, not automatic approval of a minimum design radius. Governing speed policy, comfort, climate, pavement, sight distance and transition design must be checked separately. It does not predict real tire grip in every condition.

For study and understanding, not approval of a real structure, site operation or design. Apply the correct standard, National Annex and professional review to actual engineering work.

One idea understood. Keep going.

This optional checkmark is saved only in this browser. It is your own progress note, not a certificate.

Sources & further reading

References open in a new tab and explain the underlying principles. The teaching text and examples here are SimpleFlick’s own; the source organisations have not endorsed this calculator.

Reading focus: Horizontal-curve radius. Speed, friction, curvature and stopping-distance principles. Supplied friction/reaction inputs are study data, not a driving recommendation.

Lesson updated: · Both examples and the separate practice case are checked against an independent high-precision numerical implementation. This verifies arithmetic for the stated model, not engineering certification.

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