UNDERSTAND IT. WORK IT OUT.

Learn: Member slenderness

Slenderness compares a column’s effective length with the spread of its cross-sectional area. A long member with a small radius of gyration is more slender and generally more sensitive to buckling.

Beginner-friendlyFree · No accountTwo worked examples + separate practice
01

What the formula is saying

Radius of gyration is i = √(I/A); dividing effective length by i combines length and shape into one ratio. This lesson evaluates that ratio after i has already been found.

λ = Lcr / i

Read the symbols in plain language

Lcr
Effective length

Length of the equivalent pin-ended buckling half-wave, including the effect of end restraint; it is not automatically the physical member length.

m

Metres measure length; 1 m = 1000 mm.

i
Radius of gyration

Square root of second moment divided by area, about the same axis used in the slenderness check.

m

Metres measure length; 1 m = 1000 mm.

λ
Result to find

Member slenderness. Use matching length units so the final slenderness ratio is dimensionless.

ratio / no unit

Sort out the units first

L and i must both use the same length unit. Metres divided by metres gives a dimensionless number; a radius of gyration of 30 mm is 0.03 m.

Assumptions before calculating

The effective length already represents the end restraints, and i belongs to the buckling axis being considered. Both lengths must be positive.

02

Let’s solve one together

Read the given values, follow each operation, then check what the result means.

Read the supplied values as one complete study case. Find λ and explain the result in the stated output unit.

Lcr · Effective length
3 m
i · Radius of gyration
0.03 m
  1. Identify the effective buckling length

    This is the restraint-adjusted length for the buckling plane, not automatically the clear height.

    (3) = 3 m
  2. Divide by radius of gyration

    Use matching length units so the final slenderness ratio is dimensionless.

    (3) ÷ (0.03) = 100
Answer100Dimensionless result; see the units explanation.

Does this worked answer make sense?

At fixed section, doubling effective length doubles slenderness. At fixed length, a larger i lowers slenderness.

A second worked example — different values

A second case uses different data. Predict which way the answer will change, then calculate it without reusing the first answer.

Lcr · Effective length
4 m
i · Radius of gyration
0.05 m
  1. Identify the effective buckling length

    This is the restraint-adjusted length for the buckling plane, not automatically the clear height.

    (4) = 4 m
  2. Divide by radius of gyration

    Use matching length units so the final slenderness ratio is dimensionless.

    (4) ÷ (0.05) = 80
Answer80Dimensionless result; see the units explanation.
03

Now try your own values

Change a value or its unit. The same method will show your calculation, step by step.

Length of the equivalent pin-ended buckling half-wave, including the effect of end restraint; it is not automatically the physical member length.

Square root of second moment divided by area, about the same axis used in the slenderness check.

English, Arabic and Persian digits are supported. The steps convert inputs to the formula’s base units.

Results update only when you calculate. The lesson example above stays unchanged.

04

Your turn — check your understanding

Solve this separate case yourself. Use only the values below; the two worked examples use different data. Give the requested result in the selected unit.

Lcr · Effective length
5 m
i · Radius of gyration
0.04 m

Find: Learn: Member slenderness

For repeating decimals, use at least four significant figures. Accepted rounding tolerance: 0.05% of the expected value; zero uses an absolute tolerance of 10⁻¹².

A hint, not the answer

Radius of gyration is i = √(I/A); dividing effective length by i combines length and shape into one ratio. This lesson evaluates that ratio after i has already been found.

L and i must both use the same length unit. Metres divided by metres gives a dimensionless number; a radius of gyration of 30 mm is 0.03 m.

Show the full practice solution

Compare the steps with your work; revealing a solution does not mark the lesson complete.

  1. Identify the effective buckling length

    This is the restraint-adjusted length for the buckling plane, not automatically the clear height.

    (5) = 5 m
  2. Divide by radius of gyration

    Use matching length units so the final slenderness ratio is dimensionless.

    (5) ÷ (0.04) = 125
Answer125Dimensionless result; see the units explanation.

Avoid the common trap

Do not divide metres by a radius still entered in millimetres. Do not use the section’s outside radius instead of its radius of gyration, or choose the wrong bending axis.

When this method applies — and when it does not

This is geometric slenderness, not reduced or nondimensional code slenderness. It does not include yield strength, buckling curves, local slenderness or lateral-torsional instability.

For study and understanding, not approval of a real structure, site operation or design. Apply the correct standard, National Annex and professional review to actual engineering work.

One idea understood. Keep going.

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Sources & further reading

References open in a new tab and explain the underlying principles. The teaching text and examples here are SimpleFlick’s own; the source organisations have not endorsed this calculator.

Reading focus: Member slenderness. See the Stresses in Beams and Beam Displacements modules; match the load and support conditions, not just the equation’s appearance.

Lesson updated: · Both examples and the separate practice case are checked against an independent high-precision numerical implementation. This verifies arithmetic for the stated model, not engineering certification.

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